If \[y=\frac{{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\], then \[(1-{{x}^{2}})\frac{dy}{dx}\] is equal to [RPET 1995]

If \[y=\frac{{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\], then \[(1-{{x}^{2

1.	If \[y=\frac{{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\], then \[(1-{{x}^{2}})\frac{dy}{dx}\] is equal to [RPET 1995]
A.	\[x+y\]
B.	\[1+xy\]
C.	1? xy
D.	\[xy-2\]
Answer» C. 1? xy

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If \[y=\frac{{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\], then \[(1-{{x}^{2}})\frac{dy}{dx}\] is equal to [RPET 1995]

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