If \[y=\frac{{{(1-x)}^{2}}}{{{x}^{2}}}\], then \[\frac{dy}{dx}\]is [MP PET 1999]

\[\frac{2}{{{x}^{2}}}+\frac{2}{{{x}^{3}}}\]

\[-\frac{2}{{{x}^{2}}}+\frac{2}{{{x}^{3}}}\]

\[-\frac{2}{{{x}^{2}}}-\frac{2}{{{x}^{3}}}\]

\[-\frac{2}{{{x}^{3}}}+\frac{2}{{{x}^{2}}}\]

If \[y=\frac{{{(1-x)}^{2}}}{{{x}^{2}}}\], then \[\frac{dy}{dx}\]is

1.	If \[y=\frac{{{(1-x)}^{2}}}{{{x}^{2}}}\], then \[\frac{dy}{dx}\]is [MP PET 1999]
A.	\[\frac{2}{{{x}^{2}}}+\frac{2}{{{x}^{3}}}\]
B.	\[-\frac{2}{{{x}^{2}}}+\frac{2}{{{x}^{3}}}\]
C.	\[-\frac{2}{{{x}^{2}}}-\frac{2}{{{x}^{3}}}\]
D.	\[-\frac{2}{{{x}^{3}}}+\frac{2}{{{x}^{2}}}\]
Answer» E.

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If \[y=\frac{{{(1-x)}^{2}}}{{{x}^{2}}}\], then \[\frac{dy}{dx}\]is [MP PET 1999]

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