If \[y=\frac{1}{4}{{u}^{4}},u=\frac{2}{3}{{x}^{3}}+5\], then \[\frac{dy}{dx}=\] [DSSE 1979]

\[\frac{1}{27}{{x}^{2}}{{(2{{x}^{3}}+15)}^{3}}\]

\[\frac{2}{27}x{{(2{{x}^{3}}+5)}^{3}}\]

\[\frac{2}{27}{{x}^{2}}{{(2{{x}^{3}}+15)}^{3}}\]

If \[y=\frac{1}{4}{{u}^{4}},u=\frac{2}{3}{{x}^{3}}+5\], then \[\frac{d

1.	If \[y=\frac{1}{4}{{u}^{4}},u=\frac{2}{3}{{x}^{3}}+5\], then \[\frac{dy}{dx}=\] [DSSE 1979]
A.	\[\frac{1}{27}{{x}^{2}}{{(2{{x}^{3}}+15)}^{3}}\]
B.	\[\frac{2}{27}x{{(2{{x}^{3}}+5)}^{3}}\]
C.	\[\frac{2}{27}{{x}^{2}}{{(2{{x}^{3}}+15)}^{3}}\]
D.	None of these
Answer» D. None of these

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If \[y=\frac{1}{4}{{u}^{4}},u=\frac{2}{3}{{x}^{3}}+5\], then \[\frac{dy}{dx}=\] [DSSE 1979]

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