If \[y=f\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]and \[f'(x)=\cos x\], then \[\frac{dy}{dx}=\] [MP PET 1987]

\[\frac{5x+1}{10{{x}^{2}}-3}\,\,\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]

\[\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\,\frac{dy}{dx}\,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]

\[\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]

If \[y=f\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]and \[f'(x)=\cos x\

1.	If \[y=f\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]and \[f'(x)=\cos x\], then \[\frac{dy}{dx}=\] [MP PET 1987]
A.	\[\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\,\frac{dy}{dx}\,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]
B.	\[\frac{5x+1}{10{{x}^{2}}-3}\,\,\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]
C.	\[\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]
D.	None of these
Answer» B. \[\frac{5x+1}{10{{x}^{2}}-3}\,\,\cos \,\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]

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If \[y=f\left( \frac{5x+1}{10{{x}^{2}}-3} \right)\]and \[f'(x)=\cos x\], then \[\frac{dy}{dx}=\] [MP PET 1987]

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