If \[y={{e}^{x}}\log x\], then \[\frac{dy}{dx}\]is [SCRA 1996]

\[{{e}^{x}}\left( \frac{1}{x}+x\log x \right)\]

\[{{e}^{x}}\left( \frac{1}{x}+\log x \right)\]

If \[y={{e}^{x}}\log x\], then \[\frac{dy}{dx}\]is

1.	If \[y={{e}^{x}}\log x\], then \[\frac{dy}{dx}\]is [SCRA 1996]
A.	\[\frac{{{e}^{x}}}{x}\]
B.	\[{{e}^{x}}\left( \frac{1}{x}+x\log x \right)\]
C.	\[{{e}^{x}}\left( \frac{1}{x}+\log x \right)\]
D.	\[\frac{{{e}^{x}}}{\log x}\]
Answer» D. \[\frac{{{e}^{x}}}{\log x}\]

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