MCQOPTIONS
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| 1. |
If \[y={{\cot }^{-1}}({{x}^{2}})\], then \[\frac{dy}{dx}\] is equal to [Pb. CET 2002] |
| A. | \[\frac{2x}{1+{{x}^{4}}}\] |
| B. | \[\frac{2x}{\sqrt{1+4x}}\] |
| C. | \[\frac{-2x}{1+{{x}^{4}}}\] |
| D. | \[\frac{-2x}{\sqrt{1+{{x}^{2}}}}\] |
| Answer» D. \[\frac{-2x}{\sqrt{1+{{x}^{2}}}}\] | |