1.

If \[y={{\cot }^{-1}}({{x}^{2}})\], then \[\frac{dy}{dx}\] is equal to        [Pb. CET 2002]

A.            \[\frac{2x}{1+{{x}^{4}}}\]
B.            \[\frac{2x}{\sqrt{1+4x}}\]
C.            \[\frac{-2x}{1+{{x}^{4}}}\]
D.            \[\frac{-2x}{\sqrt{1+{{x}^{2}}}}\]
Answer» D.            \[\frac{-2x}{\sqrt{1+{{x}^{2}}}}\]


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