If \[y=\cos (\sin {{x}^{2}}),\]then at \[x=\sqrt{\frac{\pi }{2}},\frac{dy}{dx}\]=

If \[y=\cos (\sin {{x}^{2}}),\]then at \[x=\sqrt{\frac{\pi }{2}},\frac

1.	If \[y=\cos (\sin {{x}^{2}}),\]then at \[x=\sqrt{\frac{\pi }{2}},\frac{dy}{dx}\]=
A.	? 2
B.	2
C.	\[-2\sqrt{\frac{\pi }{2}}\]
D.	0
Answer» E.

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If \[y=\cos (\sin {{x}^{2}}),\]then at \[x=\sqrt{\frac{\pi }{2}},\frac{dy}{dx}\]=

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