If \[y=c{{e}^{{{\sin }^{-1}}x}}\], then corresponding to this the differential equation is

\[\frac{dy}{dx}=\frac{1}{\sqrt{1-{{x}^{2}}}}\]\[\]

\[\frac{dy}{dx}=\frac{y}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{dy}{dx}=\frac{x}{\sqrt{1-{{x}^{2}}}}\]

If \[y=c{{e}^{{{\sin }^{-1}}x}}\], then corresponding to this the diff

1.	If \[y=c{{e}^{{{\sin }^{-1}}x}}\], then corresponding to this the differential equation is
A.	\[\frac{dy}{dx}=\frac{y}{\sqrt{1-{{x}^{2}}}}\]
B.	\[\frac{dy}{dx}=\frac{1}{\sqrt{1-{{x}^{2}}}}\]\[\]
C.	\[\frac{dy}{dx}=\frac{x}{\sqrt{1-{{x}^{2}}}}\]
D.	None of these
Answer» B. \[\frac{dy}{dx}=\frac{1}{\sqrt{1-{{x}^{2}}}}\]\[\]

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If \[y=c{{e}^{{{\sin }^{-1}}x}}\], then corresponding to this the differential equation is

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