MCQOPTIONS
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| 1. |
If \[y=a+b{{x}^{2}};a,b\] arbitrary constants, then [EAMCET 1994] |
| A. | \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=2xy\] |
| B. | \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}=\frac{dy}{dx}\] |
| C. | \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}-\frac{dy}{dx}+y=0\] |
| D. | \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}=2xy\] |
| Answer» C. \[x\frac{{{d}^{2}}y}{d{{x}^{2}}}-\frac{dy}{dx}+y=0\] | |