1.

If \(X(z)=\frac{4z}{{(z+0.5)}^2} ;|z|>0.5\) and impulse response h(n) = x(n). Find Y(z).

A. \( Y(z)=\frac{16z^3}{{(z+0.5)}^2} \)
B. \( Y(z)=\frac{4z^2}{{(z+0.5)}^2} \)
C. \( Y(z)=\frac{4z^3}{{(z+0.5)}^4} \)
D. \( Y(z)=\frac{16z^2}{{(z+0.5)}^4} \)
Answer» E.


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