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1. |
If x(t) is as shown in the figure, its Laplace transform is |
A. | \(\frac{{2{e^{ + 5s}} + 2{e^{ - 5s}}}}{{{s^2}}}\) |
B. | \(\frac{{2{e^{ + 5s}} - 4 + 2{e^{ - 5s}}}}{{{s^2}}}\) |
C. | \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\) |
D. | \(\frac{{2{e^{ + 5s}} + 4 - 2{e^{ - 5s}}}}{{{s^2}}}\) |
Answer» C. \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\) | |