1.

If x(t) is as shown in the figure, its Laplace transform is

A. \(\frac{{2{e^{ + 5s}} + 2{e^{ - 5s}}}}{{{s^2}}}\)
B. \(\frac{{2{e^{ + 5s}} - 4 + 2{e^{ - 5s}}}}{{{s^2}}}\)
C. \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\)
D. \(\frac{{2{e^{ + 5s}} + 4 - 2{e^{ - 5s}}}}{{{s^2}}}\)
Answer» C. \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\)


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