If x2 - 6x + 1 = 0, then the value of \({x^2} + \frac{1}{{{x^2}}}\) – McqOptions

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1.	If x2 - 6x + 1 = 0, then the value of \({x^2} + \frac{1}{{{x^2}}}\) is
A.	30
B.	34
C.	32
D.	None of the above
Answer» C. 32

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