1.

If \[{{x}^{y}}={{y}^{x}},\]then \[\frac{dy}{dx}=\]                       [DSSE 1996; MP PET 1997]

A.            \[\frac{y(x{{\log }_{e}}y+y)}{x(y{{\log }_{e}}x+x)}\]
B.            \[\frac{y(x{{\log }_{e}}y-y)}{x(y{{\log }_{e}}x-x)}\]
C.            \[\frac{x(x{{\log }_{e}}y-y)}{y(y{{\log }_{e}}x-x)}\]
D.            \[\frac{x(x{{\log }_{e}}y+y)}{y(y{{\log }_{e}}x+x)}\]
Answer» C.            \[\frac{x(x{{\log }_{e}}y-y)}{y(y{{\log }_{e}}x-x)}\]


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