If \[x=y\sqrt{1-{{y}^{2}},}\]then \[\frac{dy}{dx}=\] [MP PET 2001]

\[\frac{\sqrt{1-{{y}^{2}}}}{1+2{{y}^{2}}}\]

\[\frac{\sqrt{1-{{y}^{2}}}}{1-2{{y}^{2}}}\]

If \[x=y\sqrt{1-{{y}^{2}},}\]then \[\frac{dy}{dx}=\]

1.	If \[x=y\sqrt{1-{{y}^{2}},}\]then \[\frac{dy}{dx}=\] [MP PET 2001]
A.	0
B.	x
C.	\[\frac{\sqrt{1-{{y}^{2}}}}{1-2{{y}^{2}}}\]
D.	\[\frac{\sqrt{1-{{y}^{2}}}}{1+2{{y}^{2}}}\]
Answer» D. \[\frac{\sqrt{1-{{y}^{2}}}}{1+2{{y}^{2}}}\]

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If \[x=y\sqrt{1-{{y}^{2}},}\]then \[\frac{dy}{dx}=\] [MP PET 2001]

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