MCQOPTIONS
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| 1. |
If \[x\]takes non-positive permissible value, then \[{{\sin }^{-1}}x\]= |
| A. | \[{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] |
| B. | \[-{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] |
| C. | \[{{\cos }^{-1}}\sqrt{{{x}^{2}}-1}\] |
| D. | \[\pi -{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] |
| Answer» C. \[{{\cos }^{-1}}\sqrt{{{x}^{2}}-1}\] | |