MCQOPTIONS
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| 1. |
If x(t) is as shown in the figure, its Laplace transform is |
| A. | \(\frac{{2{e^{ + 5s}} + 2{e^{ - 5s}}}}{{{s^2}}}\) |
| B. | \(\frac{{2{e^{ + 5s}} - 4 + 2{e^{ - 5s}}}}{{{s^2}}}\) |
| C. | \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\) |
| D. | \(\frac{{2{e^{ + 5s}} + 4 - 2{e^{ - 5s}}}}{{{s^2}}}\) |
| Answer» C. \(\frac{{2{e^{ + 5s}} - 2 + 2{e^{ - 5s}}}}{{{s^2}}}\) | |