If \[x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \text{cosec}30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ },\] then \[x=\]

If \[x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}

1.	If \[x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \text{cosec}30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ },\] then \[x=\]
A.	2
B.	4
C.	8
D.	16
Answer» D. 16

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If \[x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \text{cosec}30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ },\] then \[x=\]

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