If \[x={{\sin }^{-1}}(3t-4{{t}^{3}})\] and \[y={{\cos }^{-1}}\,\,\sqrt{(1-{{t}^{2}})}\], then \[\frac{dy}{dx}\] is equal to [Kerala (Engg.) 2002]

If \[x={{\sin }^{-1}}(3t-4{{t}^{3}})\] and \[y={{\cos }^{-1}}\,\,\sqrt

1.	If \[x={{\sin }^{-1}}(3t-4{{t}^{3}})\] and \[y={{\cos }^{-1}}\,\,\sqrt{(1-{{t}^{2}})}\], then \[\frac{dy}{dx}\] is equal to [Kerala (Engg.) 2002]
A.	½
B.	2/5
C.	3/2
D.	1/3
Answer» E.

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If \[x={{\sin }^{-1}}(3t-4{{t}^{3}})\] and \[y={{\cos }^{-1}}\,\,\sqrt{(1-{{t}^{2}})}\], then \[\frac{dy}{dx}\] is equal to [Kerala (Engg.) 2002]

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