If \[x=\sec \theta +\tan \theta ,\]then \[x+\frac{1}{x}=\] [MP PET 1986]

If \[x=\sec \theta +\tan \theta ,\]then \[x+\frac{1}{x}=\] [MP PET 198

1.	If \[x=\sec \theta +\tan \theta ,\]then \[x+\frac{1}{x}=\] [MP PET 1986]
A.	1
B.	\[2\sec \theta \]
C.	2
D.	\[2\tan \theta \]
Answer» C. 2

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If \[x=\sec \theta +\tan \theta ,\]then \[x+\frac{1}{x}=\] [MP PET 1986]

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