If $$x
e 0,$$$$y
e 0$$and $$z
e 0$$and $$\frac{1}{{{x^2}}}$$+ $$\frac{1}{{{y^2}}}$$+ $$\frac{1}{{{z^2}}}$$= $$\frac{1}{{xy}}$$+ $$\frac{1}{{yz}}$$+ $$\frac{1}{{zx}}$$then the relation among x, y, z is?

Question

If $$x 
e 0,$$$$y 
e 0$$and $$z 
e 0$$and $$\frac{1}{{{x^2}}}$$+ $$\frac{1}{{{y^2}}}$$+ $$\frac{1}{{{z^2}}}$$= $$\frac{1}{{xy}}$$+ $$\frac{1}{{yz}}$$+ $$\frac{1}{{zx}}$$then the relation among x, y, z is?

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

+ y + y = 0

TuteeHUB · Answer

+ y = z

TuteeHUB · Answer

$\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 0$$

TuteeHUB · Answer

= y = z

1.	If $$x \ne 0,$$$$y \ne 0$$and $$z \ne 0$$and $$\frac{1}{{{x^2}}}$$+ $$\frac{1}{{{y^2}}}$$+ $$\frac{1}{{{z^2}}}$$= $$\frac{1}{{xy}}$$+ $$\frac{1}{{yz}}$$+ $$\frac{1}{{zx}}$$then the relation among x, y, z is?
A.	+ y + y = 0
B.	+ y = z
C.	$\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 0$$
D.	= y = z
Answer» E.

If $$x \ne 0,$$$$y \ne 0$$and $$z \ne 0$$and $$\frac{1}{{{x^2}}}$$+ $$\frac{1}{{{y^2}}}$$+ $$\frac{1}{{{z^2}}}$$= $$\frac{1}{{xy}}$$+ $$\frac{1}{{yz}}$$+ $$\frac{1}{{zx}}$$then the relation among x, y, z is?

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