If \[x\] is real, the function \[\frac{(x-a)(x-b)}{(x-c)}\] will assume all real values, provided [IIT 1984; Karnataka CET 2002]

If \[x\] is real, the function \[\frac{(x-a)(x-b)}{(x-c)}\] will assum

1.	If \[x\] is real, the function \[\frac{(x-a)(x-b)}{(x-c)}\] will assume all real values, provided [IIT 1984; Karnataka CET 2002]
A.	\[a>b>c\]
B.	\[a<b<c\]
C.	\[a>c<b\]
D.	\[a<c<b\]
Answer» E.