If \[x\in [\pi /2,\pi ]\] then\[{{\cot }^{-1}}\left( \frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}} \right)=\]

If \[x\in [\pi /2,\pi ]\] then\[{{\cot }^{-1}}\left( \frac{\sqrt{1+\si

1.	If \[x\in [\pi /2,\pi ]\] then\[{{\cot }^{-1}}\left( \frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}} \right)=\]
A.	\[\frac{x-\pi }{2}\]
B.	\[\frac{\pi -x}{2}\]
C.	\[\frac{3\pi -x}{2}\]
D.	None of these
Answer» C. \[\frac{3\pi -x}{2}\]

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If \[x\in [\pi /2,\pi ]\] then\[{{\cot }^{-1}}\left( \frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}} \right)=\]

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