If X has binomial distribution with mean np and variance npq, then \[\frac{P(X=k)}{P(X=k-1)}\] is [Pb. CET 2004]

\[\frac{n-k}{k-1}.\frac{p}{q}\]

\[\frac{n-k+1}{k}.\frac{p}{q}\]

\[\frac{n-1}{k+1}.\frac{q}{p}\]

If X has binomial distribution with mean np and variance npq, then \

1.	If X has binomial distribution with mean np and variance npq, then \[\frac{P(X=k)}{P(X=k-1)}\] is [Pb. CET 2004]
A.	\[\frac{n-k}{k-1}.\frac{p}{q}\]
B.	\[\frac{n-k+1}{k}.\frac{p}{q}\]
C.	\[\frac{n+1}{k}.\frac{q}{p}\]
D.	\[\frac{n-1}{k+1}.\frac{q}{p}\]
Answer» C. \[\frac{n+1}{k}.\frac{q}{p}\]

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If X has binomial distribution with mean np and variance npq, then \[\frac{P(X=k)}{P(X=k-1)}\] is [Pb. CET 2004]

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