If \[x+\frac{1}{x}=2\cos \alpha \], then \[{{x}^{n}}+\frac{1}{{{x}^{n}}}=\] [Karnataka CET 2004]

If \[x+\frac{1}{x}=2\cos \alpha \], then \[{{x}^{n}}+\frac{1}{{{x}^{n}

1.	If \[x+\frac{1}{x}=2\cos \alpha \], then \[{{x}^{n}}+\frac{1}{{{x}^{n}}}=\] [Karnataka CET 2004]
A.	\[{{2}^{n}}\cos \alpha \]
B.	\[{{2}^{n}}\cos n\alpha \]
C.	\[2i\,\sin \,n\,\alpha \]
D.	\[2\cos \,n\alpha \]
Answer» E.

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If \[x+\frac{1}{x}=2\cos \alpha \], then \[{{x}^{n}}+\frac{1}{{{x}^{n}}}=\] [Karnataka CET 2004]

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