If \[x={{e}^{y+{{e}^{y+....t\text{o}\,\,\infty }}}}\], \[x>0,\] then \[\frac{dy}{dx}\] is [AIEEE 2004]

If \[x={{e}^{y+{{e}^{y+....t\text{o}\,\,\infty }}}}\], \[x>0,\] then \

1.	If \[x={{e}^{y+{{e}^{y+....t\text{o}\,\,\infty }}}}\], \[x>0,\] then \[\frac{dy}{dx}\] is [AIEEE 2004]
A.	\[\frac{1+x}{x}\]
B.	\[\frac{1}{x}\]
C.	\[\frac{1-x}{x}\]
D.	\[\frac{x}{1+x}\]
Answer» D. \[\frac{x}{1+x}\]

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If \[x={{e}^{y+{{e}^{y+....t\text{o}\,\,\infty }}}}\], \[x>0,\] then \[\frac{dy}{dx}\] is [AIEEE 2004]

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