If \[x{{e}^{xy}}=y+{{\sin }^{2}}x\], then at \[x=0,\frac{dy}{dx}=\] [IIT 1996]

If \[x{{e}^{xy}}=y+{{\sin }^{2}}x\], then at \[x=0,\frac{dy}{dx}=\]

1.	If \[x{{e}^{xy}}=y+{{\sin }^{2}}x\], then at \[x=0,\frac{dy}{dx}=\] [IIT 1996]
A.	-1
B.	-2
C.	1
D.	2
Answer» D. 2

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If \[x{{e}^{xy}}=y+{{\sin }^{2}}x\], then at \[x=0,\frac{dy}{dx}=\] [IIT 1996]

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