1.

If \[x=a{{t}^{2}},y=2at\], then \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\]                   [Karnataka CET 1993]

A.            \[-\frac{1}{{{t}^{2}}}\]
B.            \[\frac{1}{2a{{t}^{3}}}\]
C.            \[-\frac{1}{{{t}^{3}}}\]
D.            \[-\frac{1}{2a{{t}^{3}}}\]
Answer» E.


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