If \[x=a\sin 2\theta (1+\cos 2\theta ),y=b\cos 2\theta (1-\cos 2\theta )\], then \[\frac{dy}{dx}=\] [Kurukshetra CEE 1998]

If \[x=a\sin 2\theta (1+\cos 2\theta ),y=b\cos 2\theta (1-\cos 2\theta

1.	If \[x=a\sin 2\theta (1+\cos 2\theta ),y=b\cos 2\theta (1-\cos 2\theta )\], then \[\frac{dy}{dx}=\] [Kurukshetra CEE 1998]
A.	\[\frac{b\tan \theta }{a}\]
B.	\[\frac{a\tan \theta }{b}\]
C.	\[\frac{a}{b\tan \theta }\]
D.	\[\frac{b}{a\tan \theta }\]
Answer» B. \[\frac{a\tan \theta }{b}\]

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If \[x=a\sin 2\theta (1+\cos 2\theta ),y=b\cos 2\theta (1-\cos 2\theta )\], then \[\frac{dy}{dx}=\] [Kurukshetra CEE 1998]

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