If \[x=A\cos 4t+B\sin 4t\],then \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=\] [Karnataka CET 2004]

If \[x=A\cos 4t+B\sin 4t\],then \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=\] [Ka

1.	If \[x=A\cos 4t+B\sin 4t\],then \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=\] [Karnataka CET 2004]
A.	? 16x
B.	16 x
C.	x
D.	? x
Answer» B. 16 x

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If \[x=A\cos 4t+B\sin 4t\],then \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=\] [Karnataka CET 2004]

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