If \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}},\] then\[{{\tan }^{-1}}\frac{xy}{zr}+{{\tan }^{-1}}\frac{yz}{xr}+{{\tan }^{-1}}\frac{xz}{yr}=\]

If \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}},\] then\[{{\tan }^{-1}}\f

1.	If \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}},\] then\[{{\tan }^{-1}}\frac{xy}{zr}+{{\tan }^{-1}}\frac{yz}{xr}+{{\tan }^{-1}}\frac{xz}{yr}=\]
A.	\[\pi \]
B.	\[\frac{\pi }{2}\]
C.	0
D.	None of these
Answer» C. 0

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If \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}},\] then\[{{\tan }^{-1}}\frac{xy}{zr}+{{\tan }^{-1}}\frac{yz}{xr}+{{\tan }^{-1}}\frac{xz}{yr}=\]

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