If \[{{x}^{2}}{{e}^{y}}+2xy{{e}^{x}}+13=0\], then dy/dx = [RPET 1987]

\[\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

\[\frac{2x{{e}^{x-y}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

\[-\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]

If \[{{x}^{2}}{{e}^{y}}+2xy{{e}^{x}}+13=0\], then dy/dx =

1.	If \[{{x}^{2}}{{e}^{y}}+2xy{{e}^{x}}+13=0\], then dy/dx = [RPET 1987]
A.	\[\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]
B.	\[\frac{2x{{e}^{x-y}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]
C.	\[-\frac{2x{{e}^{y-x}}+2y(x+1)}{x(x{{e}^{y-x}}+2)}\]
D.	None of these
Answer» D. None of these

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If \[{{x}^{2}}{{e}^{y}}+2xy{{e}^{x}}+13=0\], then dy/dx = [RPET 1987]

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