If \[x=2\cos t-\cos 2t\],\[y=2\sin t-\sin 2t\], then at \[t=\frac{\pi }{4},\frac{dy}{dx}=\]

If \[x=2\cos t-\cos 2t\],\[y=2\sin t-\sin 2t\], then at \[t=\frac{\pi

1.	If \[x=2\cos t-\cos 2t\],\[y=2\sin t-\sin 2t\], then at \[t=\frac{\pi }{4},\frac{dy}{dx}=\]
A.	\[\sqrt{2}+1\]
B.	\[\sqrt{2+1}\]
C.	\[\frac{\sqrt{2+1}}{2}\]
D.	None of these
Answer» B. \[\sqrt{2+1}\]

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If \[x=2\cos t-\cos 2t\],\[y=2\sin t-\sin 2t\], then at \[t=\frac{\pi }{4},\frac{dy}{dx}=\]

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