If \[x>0\] and \[g\] is a bounded function, then \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,\frac{f(x){{e}^{nx}}+g(x)}{{{e}^{nx}}+1}\] is

If \[x>0\] and \[g\] is a bounded function, then \[\underset{n\,\to

1.	If \[x>0\] and \[g\] is a bounded function, then \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,\frac{f(x){{e}^{nx}}+g(x)}{{{e}^{nx}}+1}\] is
A.	0
B.	\[f(x)\]
C.	\[g(x)\]
D.	None of these
Answer» C. \[g(x)\]

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If \[x>0\] and \[g\] is a bounded function, then \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,\frac{f(x){{e}^{nx}}+g(x)}{{{e}^{nx}}+1}\] is

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