1.

If we express the energy of a photon in KeV and the wavelength in angstroms, then energy of a photon can be calculated from the relation                           [AMU (Engg.) 1999]

A.            \[E=12.4\,h\nu \]               
B.            \[E=12.4\,h/\lambda \]
C.            \[E=12.4\,/\lambda \]      
D.            \[E=h\nu \]
Answer» D.            \[E=h\nu \]


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