MCQOPTIONS
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| 1. |
If we express the energy of a photon in KeV and the wavelength in angstroms, then energy of a photon can be calculated from the relation [AMU (Engg.) 1999] |
| A. | \[E=12.4\,h\nu \] |
| B. | \[E=12.4\,h/\lambda \] |
| C. | \[E=12.4\,/\lambda \] |
| D. | \[E=h\nu \] |
| Answer» D. \[E=h\nu \] | |