If \[\vec{a}\] and \[\vec{b}\] are two unit vectors and \[\theta \] is the angle between them, then the unit vector along the angular bisector of \[\vec{a}\] and \[\vec{b}\] will be given by

\[\frac{\vec{a}-\vec{b}}{\cos (\theta /2)}\]

\[\frac{\vec{a}-\vec{b}}{2\cos (\theta /2)}\]

\[\frac{\vec{a}+\vec{b}}{2\cos (\theta /2)}\]

If \[\vec{a}\] and \[\vec{b}\] are two unit vectors and \[\theta \] is

1.	If \[\vec{a}\] and \[\vec{b}\] are two unit vectors and \[\theta \] is the angle between them, then the unit vector along the angular bisector of \[\vec{a}\] and \[\vec{b}\] will be given by
A.	\[\frac{\vec{a}-\vec{b}}{2\cos (\theta /2)}\]
B.	\[\frac{\vec{a}+\vec{b}}{2\cos (\theta /2)}\]
C.	\[\frac{\vec{a}-\vec{b}}{\cos (\theta /2)}\]
D.	none of these
Answer» C. \[\frac{\vec{a}-\vec{b}}{\cos (\theta /2)}\]

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If \[\vec{a}\] and \[\vec{b}\] are two unit vectors and \[\theta \] is the angle between them, then the unit vector along the angular bisector of \[\vec{a}\] and \[\vec{b}\] will be given by

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