1.

If \[u={{\tan }^{-1}}\left( \frac{{{x}^{3}}+{{y}^{3}}}{x-y} \right)\], then \[x\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=\] [EAMCET 1999]

A. \[\sin 2u\]
B. \[\cos 2u\]
C. \[\tan 2u\]
D. \[\sec 2u\]
Answer» B. \[\cos 2u\]


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