If \[u(x,y)=y\log x+x\,\log y,\] then \[{{u}_{x}}{{u}_{y}}-{{u}_{x}}\log x-{{u}_{y}}\log y+\log x\,\,\log y=\] [EAMCET 2003]

If \[u(x,y)=y\log x+x\,\log y,\] then \[{{u}_{x}}{{u}_{y}}-{{u}_{x}}\l

1.	If \[u(x,y)=y\log x+x\,\log y,\] then \[{{u}_{x}}{{u}_{y}}-{{u}_{x}}\log x-{{u}_{y}}\log y+\log x\,\,\log y=\] [EAMCET 2003]
A.	0
B.	-1
C.	1
D.	2
Answer» D. 2

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If \[u(x,y)=y\log x+x\,\log y,\] then \[{{u}_{x}}{{u}_{y}}-{{u}_{x}}\log x-{{u}_{y}}\log y+\log x\,\,\log y=\] [EAMCET 2003]

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