1.

If \[u={{\tan }^{-1}}\left( \frac{{{x}^{3}}+{{y}^{3}}}{x-y} \right)\], then \[x\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=\]                                                                                                                [EAMCET 1999]

A.            \[\sin 2u\]
B.            \[\cos 2u\]
C.            \[\tan 2u\]
D.            \[\sec 2u\]
Answer» B.            \[\cos 2u\]


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