If \[u={{\tan }^{-1}}\frac{y}{x}\], then by Euler?s Theorem the value of x \[\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=\] [Tamilnadu (Engg.) 1993]

If \[u={{\tan }^{-1}}\frac{y}{x}\], then by Euler?s Theorem the value

1.	If \[u={{\tan }^{-1}}\frac{y}{x}\], then by Euler?s Theorem the value of x \[\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=\] [Tamilnadu (Engg.) 1993]
A.	\[\tan u\]
B.	\[\sin u\]
C.	\[0\]
D.	\[\cos 2u\]
Answer» D. \[\cos 2u\]

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If \[u={{\tan }^{-1}}\frac{y}{x}\], then by Euler?s Theorem the value of x \[\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=\] [Tamilnadu (Engg.) 1993]

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