1.

If \[u={{\sin }^{-1}}\left( \frac{y}{x} \right),\] then \[\frac{\partial u}{\partial x}\] is equal to [Tamilnadu (Engg.) 1992]

A.            \[-\frac{y}{{{x}^{2}}+{{y}^{2}}}\]
B.            \[\frac{x}{\sqrt{1-{{y}^{2}}}}\]
C.            \[\frac{-y}{\sqrt{{{x}^{2}}-{{y}^{2}}}}\]
D.            \[\frac{-y}{x\sqrt{{{x}^{2}}-{{y}^{2}}}}\]
Answer» E.


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