If \[u=\log ({{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz)\], then \[\left( \frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z} \right)\] \[(x+y+z)\] = [EAMCET 1996]

If \[u=\log ({{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz)\], then \[\left( \fra

1.	If \[u=\log ({{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz)\], then \[\left( \frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z} \right)\] \[(x+y+z)\] = [EAMCET 1996]
A.	0
B.	1
C.	2
D.	3
Answer» E.

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If \[u=\log ({{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz)\], then \[\left( \frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z} \right)\] \[(x+y+z)\] = [EAMCET 1996]

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