If \[u={{\cot }^{-1}}\sqrt{\tan \alpha }-{{\tan }^{-1}}\sqrt{\tan \alpha },\] then \[\tan \left( \frac{\pi }{4}-\frac{u}{2} \right)\] is equal to

If \[u={{\cot }^{-1}}\sqrt{\tan \alpha }-{{\tan }^{-1}}\sqrt{\tan \alp

1.	If \[u={{\cot }^{-1}}\sqrt{\tan \alpha }-{{\tan }^{-1}}\sqrt{\tan \alpha },\] then \[\tan \left( \frac{\pi }{4}-\frac{u}{2} \right)\] is equal to
A.	\[\sqrt{\tan \alpha }\]
B.	\[\sqrt{\cot \alpha }\]
C.	\[\tan \alpha \]
D.	\[\cot \alpha \]
Answer» B. \[\sqrt{\cot \alpha }\]

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If \[u={{\cot }^{-1}}\sqrt{\tan \alpha }-{{\tan }^{-1}}\sqrt{\tan \alpha },\] then \[\tan \left( \frac{\pi }{4}-\frac{u}{2} \right)\] is equal to

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