If \[\theta \]is an acute angle and \[\sin \frac{\theta }{2}=\sqrt{\frac{x-1}{2x}}\], then \[\tan \theta \] is equal to [Orissa JEE 2005]

If \[\theta \]is an acute angle and \[\sin \frac{\theta }{2}=\sqrt{\fr

1.	If \[\theta \]is an acute angle and \[\sin \frac{\theta }{2}=\sqrt{\frac{x-1}{2x}}\], then \[\tan \theta \] is equal to [Orissa JEE 2005]
A.	\[{{x}^{2}}-1\]
B.	\[\sqrt{{{x}^{2}}-1}\]
C.	\[\sqrt{{{x}^{2}}+1}\]
D.	\[{{x}^{2}}+1\]
Answer» C. \[\sqrt{{{x}^{2}}+1}\]

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If \[\theta \]is an acute angle and \[\sin \frac{\theta }{2}=\sqrt{\frac{x-1}{2x}}\], then \[\tan \theta \] is equal to [Orissa JEE 2005]

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