If then \[\frac{dy}{dx}=\] [DSSE 1980; CBSE 1980]

1.	If then \[\frac{dy}{dx}=\] [DSSE 1980; CBSE 1980]
A.	\[\frac{y[2xy-{{y}^{2}}\cos (xy)-1]}{x{{y}^{2}}\cos (xy)+{{y}^{2}}-x}\]
B.	\[\frac{[2xy-{{y}^{2}}\cos (xy)-1]}{x{{y}^{2}}\cos (xy)+{{y}^{2}}-x}\]
C.	\[-\frac{y[2xy-{{y}^{2}}\cos (xy)-1]}{x{{y}^{2}}\cos (xy)+{{y}^{2}}-x}\]
D.	None of these
Answer» B. \[\frac{[2xy-{{y}^{2}}\cos (xy)-1]}{x{{y}^{2}}\cos (xy)+{{y}^{2}}-x}\]

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If then \[\frac{dy}{dx}=\] [DSSE 1980; CBSE 1980]

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