If the roots of the equation \[{{x}^{2}}+x+1=0\] are \[\alpha ,\beta \] and the roots of the equation \[{{x}^{2}}+px+q=0\] are \[\frac{\alpha }{\beta },\frac{\beta }{\alpha }\] then \[p\] is equal to [RPET 1987]

If the roots of the equation \[{{x}^{2}}+x+1=0\] are \[\alpha ,\beta \

1.	If the roots of the equation \[{{x}^{2}}+x+1=0\] are \[\alpha ,\beta \] and the roots of the equation \[{{x}^{2}}+px+q=0\] are \[\frac{\alpha }{\beta },\frac{\beta }{\alpha }\] then \[p\] is equal to [RPET 1987]
A.	-2
B.	-1
C.	1
D.	2
Answer» D. 2

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If the roots of the equation \[{{x}^{2}}+x+1=0\] are \[\alpha ,\beta \] and the roots of the equation \[{{x}^{2}}+px+q=0\] are \[\frac{\alpha }{\beta },\frac{\beta }{\alpha }\] then \[p\] is equal to [RPET 1987]

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