If the product of roots of the equation, \[m{{x}^{2}}+6x+(2m-1)=0\] is -1, then the value of m will be [Pb. CET 1990]

If the product of roots of the equation, \[m{{x}^{2}}+6x+(2m-1)=0\] is

1.	If the product of roots of the equation, \[m{{x}^{2}}+6x+(2m-1)=0\] is -1, then the value of m will be [Pb. CET 1990]
A.	1
B.	-1
C.	\[\frac{1}{3}\]
D.	\[-\frac{1}{3}\]
Answer» D. \[-\frac{1}{3}\]

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