If the ordinate \[x=a\] divides the area bounded by x-axis, part of the curve \[y=1+\frac{8}{{{x}^{2}}}\] and the ordinates \[x=2,\text{ }x=4\] into two equal parts, then a is equal to

If the ordinate \[x=a\] divides the area bounded by x-axis, part of th

1.	If the ordinate \[x=a\] divides the area bounded by x-axis, part of the curve \[y=1+\frac{8}{{{x}^{2}}}\] and the ordinates \[x=2,\text{ }x=4\] into two equal parts, then a is equal to
A.	\[\sqrt{2}\]
B.	\[2\sqrt{2}\]
C.	\[3\sqrt{2}\]
D.	None of these
Answer» C. \[3\sqrt{2}\]

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If the ordinate \[x=a\] divides the area bounded by x-axis, part of the curve \[y=1+\frac{8}{{{x}^{2}}}\] and the ordinates \[x=2,\text{ }x=4\] into two equal parts, then a is equal to

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