If the lines \[{{l}_{1}}x+{{m}_{1}}y+{{n}_{1}}=0\] and \[{{l}_{2}}x+{{m}_{2}}y+{{n}_{2}}=0\] cuts the axes at con-cyclic points, then

\[{{l}_{1}}{{m}_{1}}={{l}_{2}}{{m}_{2}}\]

\[{{l}_{1}}{{l}_{2}}={{m}_{1}}{{m}_{2}}\]

\[{{l}_{1}}{{l}_{2}}+{{m}_{1}}{{m}_{2}}=0\]

\[{{l}_{1}}{{m}_{2}}={{l}_{2}}{{m}_{1}}\]

If the lines \[{{l}_{1}}x+{{m}_{1}}y+{{n}_{1}}=0\] and \[{{l}_{2}}x+{{

1.	If the lines \[{{l}_{1}}x+{{m}_{1}}y+{{n}_{1}}=0\] and \[{{l}_{2}}x+{{m}_{2}}y+{{n}_{2}}=0\] cuts the axes at con-cyclic points, then
A.	\[{{l}_{1}}{{l}_{2}}={{m}_{1}}{{m}_{2}}\]
B.	\[{{l}_{1}}{{m}_{1}}={{l}_{2}}{{m}_{2}}\]
C.	\[{{l}_{1}}{{l}_{2}}+{{m}_{1}}{{m}_{2}}=0\]
D.	\[{{l}_{1}}{{m}_{2}}={{l}_{2}}{{m}_{1}}\]
Answer» B. \[{{l}_{1}}{{m}_{1}}={{l}_{2}}{{m}_{2}}\]

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If the lines \[{{l}_{1}}x+{{m}_{1}}y+{{n}_{1}}=0\] and \[{{l}_{2}}x+{{m}_{2}}y+{{n}_{2}}=0\] cuts the axes at con-cyclic points, then

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