If the line \[y=mx+\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}\] touches the hyperbola \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\] at the point\[\varphi \]. Then \[\varphi \]=

\[{{\sin }^{-1}}\left( \frac{bm}{a} \right)\]

\[{{\sin }^{-1}}\left( \frac{a}{bm} \right)\]

\[{{\sin }^{-1}}\left( \frac{b}{am} \right)\]

If the line \[y=mx+\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}\] touches the h

1.	If the line \[y=mx+\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}\] touches the hyperbola \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\] at the point\[\varphi \]. Then \[\varphi \]=
A.	\[{{\sin }^{-1}}(m)\]
B.	\[{{\sin }^{-1}}\left( \frac{a}{bm} \right)\]
C.	\[{{\sin }^{-1}}\left( \frac{b}{am} \right)\]
D.	\[{{\sin }^{-1}}\left( \frac{bm}{a} \right)\]
Answer» D. \[{{\sin }^{-1}}\left( \frac{bm}{a} \right)\]

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If the line \[y=mx+\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}\] touches the hyperbola \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\] at the point\[\varphi \]. Then \[\varphi \]=

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