1.

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s, then the frequency for the second note is  [AFMC 2001]

A.            \[4\times \frac{330}{4}Hz\]   
B.            \[3\times \frac{330}{4}Hz\]
C.            \[2\times \frac{330}{4}Hz\]   
D.            \[2\times \frac{4}{330}Hz\]
Answer» C.            \[2\times \frac{330}{4}Hz\]   


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