MCQOPTIONS
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| 1. |
If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s, then the frequency for the second note is [AFMC 2001] |
| A. | \[4\times \frac{330}{4}Hz\] |
| B. | \[3\times \frac{330}{4}Hz\] |
| C. | \[2\times \frac{330}{4}Hz\] |
| D. | \[2\times \frac{4}{330}Hz\] |
| Answer» C. \[2\times \frac{330}{4}Hz\] | |